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show that when a particle is moving in SHM its velocity at a distance of √3/2 A from the mean position is half of its velocity at mean position where A is equal to amplitude of SHM

    • Posted by Ranesh Rajit 6 years, 9 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Sudarshan Sharma 6 years, 9 months ago

    V=omega*underroot Square -xsquare. Here X is root 3/2 A put value in the formula and you get omega*A/2 and as at mean position velocity is omega*a the at root3/2 distance it is v/2

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