No products in the cart.

Using the concept of kinetic theory …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Using the concept of kinetic theory of gases derive the expression for pressure of a gas exerted In The Wall of its container
  • 3 answers
One more thing add the the velocity of all the dimension of the molecules. It means let v1 is velocity in One Direction v2 in y and v3 in z then v1square +v2 square +v3square is the the total velocity. Now substitute it in the equation you will get m*vsquare/2/ here v is the total velocity of one molecule
2l/v time for 1 collisions then v/2l for collisions in one second v/2l*2mv=mv*v/l change in momentum in 1 second now force on wall by one molecule is change in momentum =mv*v/2l where v is the velocity of a molecule in one dimension similarly you can add the momentum change of all n molecules to get the total force.
It's pretty long
https://examin8.com Test

Related Questions

Project report
  • 0 answers
1dyne convert to S.I unit
  • 1 answers
Ch 1 question no. 14
  • 0 answers
√kq,qpower2 R2
  • 0 answers
2d+2d =
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App