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Limit tending to o tanX upon …

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Limit tending to o tanX upon sin 3x
  • 2 answers

Mohit Shrivastav 6 years, 10 months ago

Divide numerator and denominator by x , Then ==> limit x->0 tanx/x/sin3x/x ==> lim x->0 1/sin3x/x (lim y-->0 tany/y=1) Now multiply and divide denominator by 3 ==> lim x->0 1/sin3x*3/x*3 ==> lim x->0 1/1*3 (lim y-->0 siny/y=1) ==> 1/3 I hope, this will help you.

Lokesh Chayal 6 years, 10 months ago

1/3
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