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Derive an expression for excess pressure …

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Derive an expression for excess pressure inside the a soap bubble

    • Posted by Brajshekhar Pandey 6 years, 5 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Aman Kumar 6 years, 5 months ago

    Expression for Excess pressure inside the soap bubble.... => F-inside = Force-outside +(T×2πr)×2... =>P(inside)×(πr^2)=P(outside)×(πr^2) => Cancel out whatever is being cancelled... => P(inside)=P(outside)+4T/R => P(excess)= Pi -Po=4T/R.......Hope this helps uh...

    0Thank You

    Sb Junaid 6 years, 5 months ago

    4T/R

    1Thank You

    ANSWER
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