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Derive equation of motion of a …

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Derive equation of motion of a projectile .also find (a )time of flight (b) maximum height (c) horizontal range.

    • Posted by Rahul Kr 6 years, 9 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Macherla Indupriya 6 years, 9 months ago

    a) s=ut+1/2 at^2 0= Vsin(V not sin teta )T+1/2(-g)T^2 0=Vsin teta T-1/2gT^2 1/2gT^2=Vsin teta T 1/2gT= Vsin teta T= 2Vsin teta /g b)v^2-u^2= 2as v=0,u=vsinteta,a=-g,s=Hmax 0-v^2sin^2teta=-2gHmax v^2 sin^2 teta=2gHmax v^2 sin^2 teta/2g=Hmax c)R= (VnotCos teta)T R=( VnotCos teta)2vnot sin teta/g R=Vnot^2 sin^2teta/g.

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