If the percentage error in measurement …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Mohammed Javith 1 year, 5 months ago
- 0 answers
Posted by Pankaj Tripathi 1 year, 5 months ago
- 1 answers
Posted by Nekita Baraily 1 year, 4 months ago
- 2 answers
Posted by M D 1 year, 4 months ago
- 1 answers
Posted by Mansi Class 9Th 1 year, 5 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Payal Singh 8 years, 7 months ago
% error in measuring radius dr = 0.3%
Volume of sphere V = {tex}{4\over 3}\pi r^3{/tex}
Differentiate w.r.t to r, we get
{tex}{dV\over dr} = 4\pi r^2{/tex}
{tex}dV = 4\pi r^2dr{/tex}
% error in measuring Volume = {tex}{dV\over V}\times 100{/tex}
={tex}{4\pi r^2dr\over 4\pi r^2}\times 3\times 100 {/tex}
= {tex}3dr\times 100{/tex}
= {tex}3\times 0.3\times 100\over 100{/tex}= 0.9%
1Thank You