How to prove that √6 is …

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Posted by Kashish Matta 8 years, 7 months ago
- 1 answers
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Sukdeb Mukherjee 8 years, 7 months ago
let root 6 be rational no.
root 6 = a/b where a and b are integers , b not equal to zero and also a and b are coprime
6 = a2/b2 (squaring both sides )
6b2 = a2
b2 = a2/6
therefore 6 is a factor of a ( 6 divides a2
so 6 divides a )
let us take a= 6c
now 6b2= a2
6b2 = (6c)2 (putting value of a )
6b2 = 36c2
c2 = 6b2/36
c2 = b2/6
therefore 6 is also a factor of b ( 6 divides b2
so 6 divides b )
so 6 is a factor of a as well as b .this contradicts the fact that a and b are coprime . this is due to our assumption
that root 6 is rational
THEREFORE ROOT 6 IS IRRATIONAL
1Thank You