Derive an expression for excess pressure …
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Posted by Prachi Singh 6 years, 9 months ago
- 1 answers
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Ankit Kumar 6 years, 9 months ago
let us consider a hollow bubble of radius 'r' and internal diameter 'd' and thickness 't'.
let s= surface tension;
P= pressure intensity inside liquid bubble;
d= internal diameter of the bubble;
t= thickness;
let us cut the soap bubble into two halves
tensile force acting along the surface( inner and outer) circumferential of the cutting portion and is given by
F=s*3.14*d+s*3.14*(d+t)
as t<<d;
so d+t=d
so F = s*3.14*d+s*3.14*d;
F= 2*3.14*s*d;................................eq. 1
pressure force due to pressure intensity is given by
F= P*3.14*d2/4..........................................eq. 2
under equilibrium condition equating eq. 1 aand eq. 2
we get
2*3.14*s*d=P*3.14*d2/4
P=8*s/d.......................Answer
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