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Please solve this question..... A ball …

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Please solve this question..... A ball is thrown vertically upwards direction attains max. height of 16 m. At what height would be its velocity half of the initial velocity????
  • 1 answers

Ankit Kumar 6 years, 9 months ago

we have the equation

V2 =  U2 - 2*g*h;

as V= U/2;

so putting the value of V in above equation

(U/2)2=U2-2*g*h

2*g*h= U2 - (U/2)2

2*g*h= 3*U2/4;

h=3*U2/(8*g)........................................eq. 1

now we have to calculate the value of U;

if H is the total height;

then accroding to v2=U2-2*g*H;

v=0; 

we get 

U2 = 2*g*H

U2= 2*9.81*16;

U= 17.69 m/s

so required height can be calculated  form equation 1 as h= 11.96 m

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