Find the HCF of 612 and …
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Sia ? 6 years, 4 months ago
We have, 612 and 1314
{tex} \therefore \quad 612 = ( 2 \times 2 \times 3 \times 3 \times 17 ) = \left( 2 ^ { 2 } \times 3 ^ { 2 } \times 17 \right){/tex}
and {tex}1314 = ( 2 \times 3 \times 3 \times 73 ) = \left( 2 \times 3 ^ { 2 } \times 73 \right){/tex}.
{tex}\therefore{/tex} HCF (612,1314) = product of common terms with lowest power
{tex}= \left( 2 \times 3 ^ { 2 } \right) = ( 2 \times 9 ) {/tex}
HCF (612,1314) = 18
and LCM (612, 1314) = product of prime factors with highest power
{tex}= \left( 2 ^ { 2 } \times 3 ^ { 2 } \times 17 \times 73 \right) = ( 4 \times 9 \times 17 \times 73 ){/tex}
LCM (612, 1314) = 44676.
Hence, HCF(612, 1314) = 18
and LCM(612, 1314) = 44676.
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