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Prove that {1-tanA ÷ 1-cotA } …

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Prove that {1-tanA ÷ 1-cotA } = tan^2A
  • 1 answers

Ram Kushwah 6 years, 10 months ago

{tex}\begin{array}{l}\left(\frac{1-\mathrm{tanA}}{1-\mathrm{cotA}}\right)^2=\left(\frac{1-\mathrm{tanA}}{1-{\displaystyle\frac1{\mathrm{tanA}}}}\right)^2\\=\left(\mathrm{tanA}\frac{(1-\mathrm{tanA})}{\mathrm{tanA}-1}\right)^2\\=(-\mathrm{tanA})^2=\tan^2\mathrm A\end{array}{/tex}

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