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If A,B and C are interior angles of triangle ABC,then show that cos(B+C/2)=sinA/2

Posted by Keerthi . 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Dpsc Singh 6 years, 10 months ago

A+B+C = 180° B+C=180°-A B+C/2=90°-A/2 Cos(B+C/2)=cos(90°-A/2) Cos(B+C/2)=sin(A/2) Hence proved

3Thank You

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CBSE > Class 10 > Mathematics