A boy observes that the angle …

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Sia ? 6 years, 4 months ago
Let O be the position of the bird and B be the position of the boy. Let FG be the building and G be the position of the girl.
In {tex}\triangle{/tex}OLB,
{tex}\frac { OL } { B O }= \sin 30 ^ { \circ }{/tex}
{tex}\Rightarrow \quad \frac { O L } { 100 } = \frac { 1 } { 2 }{/tex}
{tex}\Rightarrow{/tex} OL = 50 m
OM = OL - ML
= OL - FG
= 50 - 20 = 30 m
In {tex}\triangle{/tex}OMG
{tex}\frac {OM}{OG}=sin45°=\frac{1}{√2}{/tex}
OG = OM√2 = 30 √2 = 42.3 meter
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