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1/(cosecA--cotA) --1/sinA =1/sinA -- 1/(cosecA+cotA)

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1/(cosecA--cotA) --1/sinA =1/sinA -- 1/(cosecA+cotA)

Posted by Deepu Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Shubhi Tyagi 6 years, 10 months ago

For this question you have to change the location of LHS and RHS..... LHS: = 1/(CosecA-CotA) - 1/(cosecA+CotA) =CosecA+CotA+CosecA-CotA/Cosec^2A - Cot^2A =2cosecA RHS: =1/sinA + 1/sinA =2/sinA =2CosecA Proved!!!!

1Thank You

Yuvraj Verma 5 years, 8 months ago

2Thank You

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CBSE > Class 10 > Mathematics