a copper wire, when bent in …

Given that Area of the square formed by bending a copper wire = 484cm^2. We know that side of the square = s^2                                  s^2 = 484                                  s = 22cm. We know that perimeter of the square = 4 * s                                                                  = 4 * 22                                                                  = 88cm. Therefore the length of the wire = 88cm. Now, Given that the same wire is bent into a form of circle. Circumference of circle = Length of wire 2pir = 88 2 * 22/7 * r = 88 44/7 * r = 88 44 * r = 88 * 7 44 * r = 616 r = 616/44 r = 14. We know that Area of circle = pir^2                                                 = 22/7 * (14)^2                                                 = 22 * 14 * 2                                                 = 616cm^2. Therefore the area enclosed by the circle = 616cm^2. Hope this helps! ---------------- Gud Luck