A man arranges to pay a …

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Ram Kushwah 6 years, 9 months ago
AS The man planned to pay Rs 3600 in 40 installmetnts
So S40=3600=40/2(2a+39d)
3600 / 20 = 2a+39d
2a+39d=180 -------(1)
Now as 1/3rd of debt is left to pay,so paid by man
=(1-1/3)*3600=2/3*3600=2400
So S30=2400
30/2(2a+29d)=2400
2a+29d=2400/15
2a+29d=160-------(2)
Now subtracting (02 ) from (1)
10d=20
d=2 Rs
Now putting d=20 in (1)
2a+39*2=180
2a=180-78=102
a=51 Rs
So first installment =Rs 51
1Thank You