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Find the value of 'k' so that equations have equal roots Kx(x-2) +6=0

Posted by Mayank Pruthi 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Ronak Jain 6 years, 9 months ago

D=b2- 4ac=0 (-2k)2 -4(k)(6)=0 (4k)2-4k(6)=0 16k2-24k=0 16k2=24k K=6

1Thank You

Amaresh Basu 6 years, 9 months ago

Kx (x-2)+6=0 => kx^2-2kx+6=0 Now this equation has equal roots Therefore D=0 =>b^2-4ac=0 =>(-2k)^2-4×k×6=0 =>4k^2-24k=0 =>4k (k-6)=0 =>k=0 or k=6

0Thank You

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