the length of the hypotenuse of …

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Ram Kushwah 6 years, 9 months ago
Let base =x
then hypo=x+1
Let altitude =h
also hypo=2h+3
h=(hypo-3)/2------(1)
=(x+1-3)/2=(x-2)/2
Now Hypo2=h2+x2
(x+1)2=1/4*(x-2)2 +x2
{tex}\begin{array}{l}4(x+1)^2=(x-2)^2+4x^2\\4x^2+8x+4=x^2-4x+4+4x^2\\x^2-12x=0\\x(x-12)=0\\x=0\;or\;12\\\end{array}{/tex}
The side can not be zero
so x= base =12 cm
Hypo=12+1=13 cm
From(1)
h=(13-3)/2= 5 cm
0Thank You