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Prove that tan(45+x)=sec2x+tan2x

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Prove that tan(45+x)=sec2x+tan2x

    • Posted by Gopal Mahaseth 6 years, 9 months ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Sriram Kishor 4 years, 11 months ago

    LHS = Tan(45° + x ) =(Tan45° +Tan45°)/(1-Tanx.Tan45°) =(Tanx + 1)/( 1- Tanx ) =( Sinx/cosx + 1)./( 1- sinx/cosx) =(sinx + cosx )/(cosx - sinx) =(sinx +cosx )(cosx - sinx)/(cosx -sinx)² =(sin²x -cos²x)/(1-sin2x) =cos2x/(sin2x -1) =1/(sin2x - 1)/cos2x =1/(tan2x - sec2x ) =(tan2x + sec2x )= RHS

    2Thank You

    Sb Junaid 6 years, 9 months ago

    Put the formulaa

    2Thank You

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