We know that, If the quadratic equation ax²+bx+c=0 whose roots are equal then it's deteminant is equal to zero. (a-b)x²+(b-c)x+(c-a)=0 Deteminant =0 (b-c)² -4(a-b)(c-a)==0 b²+c²-2bc-4ac+4a²+4bc-4ab=0 b²+c²+4a²+4bc-4ac-4ab=0 b²+c²+(-2a)²+2bc+2c(-2a)+2(-2a)b=0 (b+c-2a)²=0 b+c-2a=0 Therefore, b+c=2a Hence proved.

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Nitin Dadhich 6 years, 9 months ago

भाई आगे भी करना है।

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Malikul Islam 6 years, 9 months ago

B²-4ac=0

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