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Gaurav Seth 6 years, 9 months ago
a=2,sum of first five terms =1/4th sum of next five terms
this gives,, 4 times of sum of first five terms =sum of next five terms
sum of first five terms + sum of next five terms = to sum of first ten terms
sum of first five terms + 4 times of sum of first five terms=sum of first ten terms
5 times of sum of first five terms =sum of first ten terms
5*n/2[2a+4d]=n/2[2a+9d] :(a=2}
5*5/2[4+4d]=10/2[4+9d]
25/2[4+4d]=5[4+9d]
5[4+4d]=2[4+9d]
20+20d=8+18d
so,d= -6
a20 = a+ 19d
= 2 + 19(-6)
= 2 - 114
= -112
2Thank You