The length of the hypotenunes of …

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Gaurav Seth 6 years, 9 months ago
Let hypotenuse be a
Given, base = a-2 ---------------- (1)
Given, altitude = (a-1)/2. ---------------- (2)
By Pythagoras theorem
a^2 = (a-2) + ((a-1)/2)^2
a^2 = (a^2-2a+1)/4 + a^2-4a+4
4a^2 = a^2-2a+1+4(a^2-4a+4)
4a^2 = a^2-2a+1+4a^2-16a+16
a^2 - 18a + 17 =0
(a-17)(a-1) = 0
a = 17
Substitute a = 17 in (2) we get
and lenght of each side = 17 - 1/2
= 16/2
= 8
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