Sin square thitha plus cos four …
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Ram Kushwah 6 years, 9 months ago
{tex}\begin{array}{l}\sin^4\theta-\cos^4\theta\\=(\sin^2\theta+\cos^2\theta)((\sin^2\theta-\cos^2\theta)\\\sin^4\theta-\cos^4\theta=\sin^2\theta-\cos^2\theta\\or\;\;\sin^4\theta+\cos^2\theta=\cos^4\theta+\sin^2\theta\\or\;\sin^2\theta+\cos^4\theta=\;\sin^4\theta+\cos^2\theta\end{array}{/tex}
Hence proved
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