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If the two two digit numbers are placed one after the other to form a four digit number such that the larger number is placed first. The difference between the four digit number and the sum of two two digit mumber is 5742. Then find the numbers.

Posted by Shikhar Singh 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 9 months ago

Let the numbers are xy=10x+y and ab=10a+b

then 4 digit no=xyab=1000x+100y+10a+b

Now 1000x+100y+10a+b-(10x+y+10a+b)=5742

990x+99y=5782

or 10x+y=58

so first No=58

For 2nd No . other condition is required so the question is incomplete

By trial and error method:

take a=1 and b=1

Then 5811-(58+11)=5811-69=5742

again if a-=1 b=2

Then 5812-(58+12)=5812-70=5742

again if a-=2 b=3

Then 5823-(58+23)=

=5800+23-58-23=5800-58=5742

So So many solutions are possible but fist number 58 is sure

0Thank You

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