Find the sum of n terms …

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Posted by Jyoti Yadav 6 years, 9 months ago
- 3 answers
Ram Kushwah 6 years, 9 months ago
Series becomes:
4x n-1/n(1+2+3+.......n)
=4n-1/n*n(n+1)/2
=4n-(n+1)/2
=1/2(8n-n-1)
={tex}\frac{7n-1}{2}{/tex}
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Ram Kushwah 6 years, 9 months ago
Sum=4n-1/n(1+2+3+........n)
=4n-1/n*n(n+1)/2
=4n-(n+1)/2
=1/2(8n-n-1)
=1/2(7n-1)
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