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Find the sum of n terms …

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Find the sum of n terms of the series (4-1/n)+(4-2/n)+(4-3/n)+............
  • 3 answers

Ram Kushwah 6 years, 9 months ago

Sum=4n-1/n(1+2+3+........n)

=4n-1/n*n(n+1)/2

=4n-(n+1)/2

=1/2(8n-n-1)

=1/2(7n-1)

Ram Kushwah 6 years, 9 months ago

Series becomes:

4x n-1/n(1+2+3+.......n)

=4n-1/n*n(n+1)/2

=4n-(n+1)/2

=1/2(8n-n-1)

={tex}\frac{7n-1}{2}{/tex}

Amit Kumar 6 years, 9 months ago

3n
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