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In given fig op is equal …

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In given fig op is equal to the diameter of a circle with centre o and pa pb are two tangents prove that abp is equilateral triangle

    • Posted by Abhi Gubbi 6 years, 9 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Ram Kushwah 6 years, 9 months ago

    In {tex}\triangle{/tex}AOP

    OP=2r and OA =r

    SO sin APO=OA/OP=r/2r=1/2=sin 30

    So {tex}\angle APO=30 {/tex}

    Similarly {tex}\angle BPO=30 {/tex}

    So {tex}\angle APB=30+30=60 {/tex}

    Now in {tex}\triangle{/tex}APB  

    {tex}\angle PAB=\angle PBA {/tex} (as PA=PB)

    so {tex}\angle PAB=\angle PBA=\angle APB=60 {/tex}

    Hence {tex}\triangle{/tex}PAB is an equilateral triangle

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