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7 yeqrs ago Mothers age was …

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7 yeqrs ago Mothers age was 5 times the square of Daughters age. After 3 years from now Daughters age will Be 2/5 times the age of Mother. Find the difference between the ages of Mother and Daughter? Guys plz answer fast！！！！！！！

Posted by Zarfa Umer 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

#Miss_Raagini ???? 6 years, 9 months ago

Given – 7 years ago x – 7 = 5(y-7)^2 ----------------1 Also given – 3 years hence y + 3 = 2/5 (x + 3) 5y + 15 = 2x + 6 2x = 5y + 9 x = (5y + 9)/2 ------------------2 Substitute the value of x in equation 1 (5y + 9)/2 – 7 = 5 (y-7)^2 5y + 9 – 14 = 10 (y^2 – 14y + 49) 5y – 5 = 10y^2 – 140y + 490 10y^2 – 145y + 495 = 0 Dividing the equation by 5 2y^2 – 29y + 99 = 0 Solving above quadratic equation to find y y = (-b + sqrt (b^2 – 4ac))/4ac or y = (-b - sqrt (b^2 – 4ac))/4ac get y = 9 and y = 11/2 consider age as a whole number Therefore, y = 9 years Substitute the value of y in equation 2 Therefore, x = (5 * 9 + 9)/ 2 = 27 years

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