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x(sin)3A+y(cos)3A=sinA×cosA and xsinA=ycosA , prove that …

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x(sin)3A+y(cos)3A=sinA×cosA and xsinA=ycosA , prove that x2+y2= 1

Posted by Vishu Gupta 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Puja Sahoo 6 years, 9 months ago

x sinA×sin^2A + y cosA×cos^2A = sinA ×cosA.... x sinA × sin^2A + x sinA × cos^2A= sinA×cosA... as xsinA=ycosA..... ab common le jao xsinA ko yu will get x=cosA and y= sinA.... and we know that sin^2A+ cos^2A=1... so, x^2+y^2=1... proved

2Thank You

Anushka Jugran❣️ 6 years, 9 months ago

x sin^3A me se xsinA baahar lelo.. Then xsinA ki jagah ycosA put karo.. Then if u solve u will get y=sin A nd x=cosA... Phir ye value vahan daal do jahan aapko proof karna hai..

2Thank You

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CBSE > Class 10 > Mathematics