If the radius of the circle …

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Ram Kushwah 6 years, 9 months ago
Let angle of arc ={tex}\theta{/tex}
{tex}\begin{array}{l}\mathrm{Length}\;\mathrm{of}\;\mathrm{arc}=\frac{\mathrm\theta}{360}\times2\mathrm{πr}\\\mathrm{so}\;\frac{\mathrm\theta}{360}\times2\mathrm\pi\times6=12\\\frac{\mathrm{θπ}}{360}=1.....(1)\\\mathrm{now}\;\mathrm{area}\;\mathrm{of}\;\mathrm{sector}\\=\frac{\mathrm\theta}{360}\times\mathrm{πr}^2=1\times\mathrm r^2=\mathrm r^2\;(\;\mathrm{from}\;(1))\\=6^2=36\;\mathrm{cm}^2\end{array}{/tex}
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