A circus tent is a cylindrical …

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Sia ? 6 years, 4 months ago
Radius of the cone = 52.5m

Height of the cylinder = 3m
Slant height of the cone = 53m
Area of the canvas = curved surface area of cone + curved surface area of cylinder = 2{tex}\pi{/tex} rh + {tex}\pi{/tex}rl
{tex}= \left( 2 \times \frac { 22 } { 7 } \times 52.5 \times 3 + \frac { 22 } { 7 } \times 52.5 \times 53 \right) \mathrm { m } ^ { 2 }{/tex} {tex}{/tex}
{tex}= \frac { 22 } { 7 } \times 52.5 ( 6 + 53 ) \mathrm { m } ^ { 2 } = 9735 \mathrm { m } ^ { 2 }{/tex}
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