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Find the number nearest to 110000 …

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Find the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21

Posted by Aman Shuklq 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Gaurav Seth 6 years, 9 months ago

The number which is divisible by 8, 15 and 21 is also divisible by the L.C.M. of the number.
The L.C.M. of 8, 15 and 21 is =
8 = 2 × 2 × 2
15 = 3 × 5
21 = 3 × 7
L.C.M. = 2 × 2 × 2 × 3 × 5 × 7 = 840
If we divide 110000 by 840, we will find out that it is not exactly divisible and we get 800 as remainder.
Thus the number nearest to 110000 but greater than 100000 which is exactly divisible by 840 and also divisible by 8, 15 and 21 is
= 110000 - 840 = 109200
Hence 109200 is exactly divisible by 8, 15 and 21.

0Thank You

Thunder ?Yashwanth??? 6 years, 9 months ago

Find the hcf and then divide 110000 then you will get a remainder . Subtract that remainder from 110000.?

0Thank You

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