How many terms of the AP: …

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Yogita Ingle 6 years, 9 months ago
First term of A.P. = 9 , common difference = 8
if sum of n terms 636, Sn = (n/2) [ 2×9 + (n-1)8 ] = 636
Sn = n [ 10+ 8n] = 1272
8n2 +10n -1272 = 0
4n2 +5n -636 = 0
By factorising LHS,
(4n+53)(n-12) = 0
hence n = 12
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