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From an external point P tangents …

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From an external point P tangents PA and PB are drawn to a circle with Centre o if CD is it and CD is the tangent to the circle at a point a and b is equal to 14 cm find the perimeter of triangle PCD

Posted by Vishal Vishwakarma 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We have,

AC = CE, BD = DE
And, AP = BP = 14 cm
{tex}\therefore{/tex} Perimeter of {tex}\Delta{/tex}PCD = PC + CD+ PD
{tex}\Rightarrow{/tex} Perimeter of {tex}\Delta{/tex}PCD = PC + (CE + ED) + PD
= (PC + CE) + (ED + PD)
= (PC + AC) + (BD + PD)
= PA + PB
= 14 + 14
= 28
{tex}\therefore{/tex} Perimeter of {tex}\triangle{/tex}PCD = 28 cm.

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