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prove :- sinA-2sin cube A / …

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prove :- sinA-2sin cube A / 2cos cube A-cosA= tan A
  • 4 answers

Gautam Nirmaan Gautam Nirmaan 6 years, 9 months ago

L.H.S.= sinA-2sin cube A / 2cos cube A - cosA =sinA(1-2sin square A) / cosA(2cos square A -1) =tanA[1 - 2sin square A / 2(1 - sin square A) - 1] = tanA[1 - 2sin square A / 2 - 2sin square A - 1] = tanA[1-2sin square A / 1-2sin square A] = tanA×1 = tanA = R.H.S.

Nitin Dadhich 6 years, 10 months ago

Ncert is useful

Affu 😊 6 years, 10 months ago

Ncert .. chapter trignometry ka exercise 8.4 question 5th ka (VII)

Sarthak Paliwal 6 years, 10 months ago

Ncert ka h ex 8.4
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