A 7m long flagstaff is fixed …

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Sia ? 6 years, 4 months ago
{tex}\frac { x } { y } = \tan 45 ^ { \circ } = 1{/tex}
{tex}\Rightarrow {/tex} x = y
Now in big triangle
tan 60o = {tex}\frac {x+7}x{/tex}
√3 = {tex}\frac {x+7}x {/tex}
{tex}x(√3-1) = 7{/tex}
So height of the tower
{tex}x=\frac{\gamma}{1.73-1}=9.58{/tex}
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