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Find the point on the x-axis …

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Find the point on the x-axis which is equidistant from (2,5) (-2,9)??

Posted by Rahul Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

? ? 6 years, 10 months ago

Yogita ingle plz explain about balkan crisis..

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? ? 6 years, 10 months ago

(-7,0)

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Yogita Ingle 6 years, 10 months ago

Let the point of x-axis be P(x, 0)
Given A(2, 5) and B(-2, 9) are equidistant from P
That is PA = PB
Hence PA² = PB² → (1)
Distance between two points is √[(x₂ - x₁)² + (y₂ - y₁)²]
PA = √[(2 - x)² + (5 - 0)²]
PA² = 4 - 4x +x² + 25 = x²- 4x + 29
Similarly, PB² = x²+ 4x + 85
Equation (1) becomes
x²- 4x + 29 = x²+ 4x + 85
- 8x = 56
x = -7
Hence the point on x-axis is (-7, 0)

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