If tanA=0.75 find the value of …

{tex}% MathType!MTEF!2!1!+- % feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaaciGG0b % Gaaiyyaiaac6gacaaMc8Uaamyqaiabg2da9iaaicdacaGGUaGaaG4n % aiaaiwdaaeaaciGG0bGaaiyyaiaac6gacaaMc8Uaamyqaiabg2da9m % aalaaabaGaaG4maaqaaiaaisdaaaaabaGaciiDaiaacggacaGGUbGa % amyqaiabg2da9maalaaabaGaamiCaiaadwgacaWGYbGaamiCaiaadw % gacaWGUbGaamizaiaadMgacaWGJbGaamyDaiaadYgacaWGHbGaamOC % aaqaaiaadkgacaWGHbGaam4CaiaadwgaaaaabaGaamiAaiabg2da9m % aakaaabaGaamiCamaaCaaaleqabaGaaGOmaaaakiabgUcaRiaadkga % daahaaWcbeqaaiaaikdaaaaabeaaaOqaaiaadIgacqGH9aqpdaGcaa % qaaiaaiodadaahaaWcbeqaaiaaikdaaaGccqGHRaWkcaaI0aWaaWba % aSqabeaacaaIYaaaaaqabaaakeaacaWGObGaeyypa0JaaGynaaaaaa!6AF2! \eqalign{ & \tan \,A = 0.75 \cr & \tan \,A = {3 \over 4} \cr & \tan A = {{perpendicular} \over {base}} \cr & h = \sqrt {{p^2} + {b^2}} \cr & h = \sqrt {{3^2} + {4^2}} \cr & h = 5 \cr} {/tex}{tex}% MathType!MTEF!2!1!+- % feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaaciGGZb % GaaiyAaiaac6gacaWGbbGaeyypa0ZaaSaaaeaacaWGWbaabaGaamiA % aaaacqGH9aqpdaWcaaqaaiaaiodaaeaacaaI1aaaaaqaaiGacogaca % GGVbGaai4CaiaaykW7caWGbbGaeyypa0ZaaSaaaeaacaWGIbaabaGa % amiAaaaacqGH9aqpdaWcaaqaaiaaisdaaeaacaaI1aaaaaqaaiGaco % hacaGGPbGaaiOBaiaaykW7caWGbbGaey4kaSIaci4yaiaac+gacaGG % ZbGaaGPaVlaadgeacqGH9aqpdaWcaaqaaiaaiodaaeaacaaI1aaaai % abgUcaRmaalaaabaGaaGinaaqaaiaaiwdaaaaabaGaci4CaiaacMga % caGGUbGaaGPaVlaadgeacqGHRaWkciGGJbGaai4BaiaacohacaaMc8 % Uaamyqaiabg2da9maalaaabaGaaG4naaqaaiaaiwdaaaaaaaa!67BD! \eqalign{ & \sin A = {p \over h} = {3 \over 5} \cr & \cos \,A = {b \over h} = {4 \over 5} \cr & \sin \,A + \cos \,A = {3 \over 5} + {4 \over 5} \cr & \sin \,A + \cos \,A = {7 \over 5} \cr} {/tex}