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Find the discriminant of the equation …

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Find the discriminant of the equation 3x²-2x+1/3=0 hence find the nature of its root Find them they are real root?

Posted by Gaurav Pandey 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Bhavya Vardhan Jain 6 years, 10 months ago

F(x)=3x²-2x+1/3 D=b²-4ac =(-2)²-4(3)(1/3) =4-4 D=0 Hence roots are real and equal x=-b±√d/2a =2±√0/6 =2/6 =1/3 Hence roots are 1/3 and 1/3. Ans

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Garima Choudhary 6 years, 10 months ago

D= b^2 - 4ac when we will solve this equation by taking LCM it will be. 9x^2 -6x +1=0 D =(-6)^2 - 4(1)(9) D = 36—36 . D=0. So the above equation has equal and real roots

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