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The factorisation of 3x²-15x+28

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The factorisation of 3x²-15x+28

    • Posted by ?Kishor Joshi? 6 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Abhay Modi 6 years, 10 months ago

    L.C.M. of 3×28=74; 3 74 2 28 2 14 7 Therefore, 3x^2-15x+28 =>3x^2-12x-7x+28 =>3x(x-4)-7(x-4) =>(x-4)(3x-7) Then, (x-4)=0 and (3x-7)=0 Theefore, x=4 and x=7/3 Now,4 and 7/3 are the roots of the given equation 3x^2-15x+28

    1Thank You

    Garima Choudhary 6 years, 10 months ago

    If we find discriminant it will be( -111) which means that it does not have real roots

    0Thank You

    Nidhi Chaudhary 6 years, 10 months ago

    No real roots

    0Thank You

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