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cos A — sinA + 1 …

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cos A — sinA + 1 ÷ cosA + sinA — 1 = cosecA + cotA. Prove using cosec square A = 1+cot square A

Posted by Josmy Wency 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Khushi Agrawal 6 years, 10 months ago

=[CosA—SinA +1/CosA+Sin—1]×[CosA +SinA +1/CosA +SinA +1] =[Cos²A+CosA.SinA+CosA—CosA.SinA—Sin²A—SinA+CosA+SinA+1]/(CosA+SinA)²—(1)² =[Cos²A+2CosA+1—Sin²A]/[Cos²A+Sin²A+2SinACosA—1]---- [:CosA.SinA—CosA.SinA=0, SinA—SinA=0] ----=[2Cos²A+2CosA]/[1—1+2SinA.CosA]---- [:1—Sin²A=Cos²A and Cos²A+Sin²A=1] =[2CosA(CosA+1)/[2SinA.CosA] =CosA+1/SinA---- ----[2CosA/2CosA=1] =CosA/SinA+1/SinA =CotA+CosecA, Hence Prooved

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Deepanshi Mittal 6 years, 10 months ago

It's N.C.E.R.T ques

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