If 4tan theta = 3 evaluate …

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Ram Kushwah 6 years, 10 months ago
LET x=theta
tanx=3/4
sec2 x=(1+tan2x)=(1+9/16)=25/16
sec x=5/4 ,cos x =4/5
sin2x=(1-16/25)=9/25 so sinx=3/5
Now (4sinx -cos x+1)/(4sinx+cosx-1)
=(4*3/5-4/5+1)/(4*3/5+4/5-1)
=(12/5-4/5+5/5)/(12/5+4/5-5/5)
=(12-4+5)/12+4-5)
=13/11
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