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If -5 is a root of equation 2x square+ px -15=0 and p(x square+x)+k=0 has equal roots.Find value of k

Posted by Krishna Parashar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Nitin Dadhich 6 years, 10 months ago

-140 is the value of K

0Thank You

Abhay Modi 6 years, 10 months ago

As -5 is a root of the equation 2x^2+px-15=0 so it is also a root of the equation p(x^2+x)+k=0 Now, 2x^2+px-15=0 =>2(-5)^2+p(-5)-15=0 =>2×25-5p-15=0 =>50-5p-15=0 =>35-5p=0 =>-5p=-35 =>5p=35 =>p=7 Now,putting p=7 and x=-5 in the equation p(x^2+x)+k=0, we get, p(x^2+x)+k=0 =>7{(-5)^2+(-5)}+k=0 =>7(25-5)+k=0 =>7×20+k=0 =>140+k=0 =>k=-140

2Thank You

Aditya Sharma Sarswat 6 years, 10 months ago

Not sure but shayad k = √5/4

1Thank You

Karan Kumar 6 years, 10 months ago

Take x = -5

0Thank You

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Posted by Hari Anand 6 months, 3 weeks ago

CBSE > Class 10 > Mathematics

0 answers

X-y=5

Posted by Kishan Thakur 1 month, 2 weeks ago

CBSE > Class 10 > Mathematics

1 answers

Don't post personal information, mobile numbers and other details.
Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Posted by Kanika . 1 month, 2 weeks ago

CBSE > Class 10 > Mathematics