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Without using trigonometric tables,prove that tan48°tan23°tan42°tan67°=1

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Without using trigonometric tables,prove that tan48°tan23°tan42°tan67°=1

    • Posted by Khan Fardin 6 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 4 answers

    Puja Sahoo? 6 years, 10 months ago

    Are, dekho... tan(90-thita) = cot thita.... so agar tan 48 hai use tan(90-42) likha.... or use, cot 42° samjhe..... ab cot 42 × tan 42 = 1/tan42×tan42=1..... samjhe

    1Thank You

    Khan Fardin 6 years, 10 months ago

    Puja ni smj aaya yar

    1Thank You

    Puja Sahoo? 6 years, 10 months ago

    tan 48° tan 23° tan 42° tan 67° = tan (90° - 42°) tan (90° - 67°) tan 42° tan 67° = cot 42° cot 67° tan 42° tan 67° = (cot 42° tan 42°) (cot 67° tan 67°) = 1×1 = 1...............proved

    3Thank You

    Harshit Sharma 6 years, 10 months ago

    Tan48° Tan23° Tan(90-48) Tan(90-23). Tan48 Tan23 Cot48 Cot23. 1

    1Thank You

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