If x=y^z , y=z^x , z=x^y …

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Ram Kushwah 6 years, 10 months ago
{tex}\begin{array}{l}\mathrm x=\mathrm y^{\mathrm z},\mathrm y=\mathrm z^{\mathrm x},\mathrm z=\mathrm x^{\mathrm y}\\\mathrm{xyz}=\mathrm x^{\mathrm y}\mathrm y^{\mathrm z}\mathrm z^{\mathrm x}\\\mathrm{xyz}=\mathrm{xyz}(\mathrm x^{\mathrm y-1}\mathrm y^{\mathrm z-1}\mathrm z^{\mathrm x-1})\\\mathrm{or}\;\mathrm x^{\mathrm y-1}\mathrm y^{\mathrm z-1}\mathrm z^{\mathrm x-1}=1\\\frac{\mathrm x^{\mathrm y}\mathrm y^{\mathrm z}\mathrm z^{\mathrm x}}{\mathrm{xyz}}=1\\\mathrm{So}\;\;\mathrm{xyz}=\mathrm x^{\mathrm y}\mathrm y^{\mathrm z}\mathrm z^{\mathrm x}\end{array}{/tex}
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