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Two electric bulbs p and q …

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Two electric bulbs p and q have their resistance in the ratio of 1:2. They are connected in series across a battery. Find the ratio of the power dissipation in these bulbs
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Sachin B 7 years, 1 month ago

Hello Dear. Given :- Ratio of the Resistance of two bulbs P and Q = 1 : 2. Let the Resistance of the bulbs P and Q be x and 2x respectively. ∵ Current remains same in the series, ∴ Let the current in the Resistors P and Q be I. Now,  For Bulbs P, Power = P₁ Current = I Resistance = x ∵ Power = I² × R ∴ P₁ = I² × x For Bulb Q, Power = P₂ Current = I Resistance = 2x ∴ Power(P₂) = I² × 2x ∴ Ratio of the Powers, P₁/P₂ = I²x/I²2x P₁/P₂ = 1/2 ⇒ P₁ : P₂ = 1 : 2 Hence, the Ratio between the Power Dissipation of the bulb P and bulb Q is 1 : 2.
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