(1+cotA+tanA)(sinA-cosA) =sinAtanA-cotAcosA

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Posted by Ansh-_## Choudhary 6 years, 10 months ago
- 2 answers
Gaurav Seth 6 years, 10 months ago
(1+cotA+tanA)(sinA-cosA)
= (sinA+sinAcotA +tanAsinA-cosA -cosAcotA -tanAcosA)
=(sinA+sinAcosA/sinA+tanAsinA-cosA-cosAcotA -cosAsinA/cosA)
= (sinA+cosA+tanAsinA -cosA- cosAcotA -sinA)
= tanAsinA -cosAcotA
= sinAtanA-cotAcosA
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Tera Baap 6 years, 10 months ago
2Thank You