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subtract y+3yz+z to 2y+yz+z

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subtract y+3yz+z to 2y+yz+z

Posted by Manjula Singh 6 years, 9 months ago

CBSE > Class 07 > Mathematics

3 answers

Ayush Thakkar 6 years, 9 months ago

The equation formed is: 2y+yz+z -(y+3yz+z) =2y+yz+z-y-3yz-z =-3yz+yz+2y-y+z-z =-2yz+y The rules that we have to use r that: - × - becomes + - × + becomes - + × - becomes - And last but not least + × + becomes + And the second rule we have to follow is also that the number with a variable always comes first. Later all the double and the single variables r placed.

0Thank You

Ram Kushwah 6 years, 9 months ago

2y+yz+z -( y+3yz+z )

=2y+yz+z-y-3yz-z

=y-2yz

0Thank You

Nihar Borah 6 years, 9 months ago

-2yz

2Thank You

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Posted by Shree Vanshika Reddy Reddy 3 months ago

CBSE > Class 07 > Mathematics