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k2x3-kx2+3k-k find the value of k …

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k2x3-kx2+3k-k find the value of k where x=3

  • 1 answers

Rashmi Bajpayee 8 years, 7 months ago

k2x3 - kx2 + 3k - k = 0

=>  k2(3)3 - k(3)2 + 3k - k = 0

=>  27k2 - 9k + 3k - k = 0

=>  27k2 - 7k = 0

=>  k(27k - 7) = 0

=> k = 0 or 27k - 7 = 0

=> k = 0 or k = 7/27

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