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Find the value of k for …

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Find the value of k for which the pair of linear equations kx + 3 Y is equals to K - 2 and 12 x + k y is equals to K has no solutions

Posted by Akhil Gavara 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Ram Kushwah 6 years, 10 months ago

kx+3y-k+2=0

12x+ky-k=0

Eqns are having no solution if

{tex}\begin{array}{l}\frac{\mathrm k}{12}=\frac3{\mathrm k}\neq\frac{-\mathrm k+2}{-\mathrm k}\\\mathrm{or}\;\mathrm k^2=12\times3=36\\\mathrm k=\pm6\end{array}{/tex}

1Thank You

Tera Baap 6 years, 10 months ago

And value for k by which above question No solution is +Or -6

1Thank You

Tera Baap 6 years, 10 months ago

K is not equal to 5

0Thank You

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