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Prove that the tangent drawn at …

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Prove that the tangent drawn at the midpoint of an Arc of a circle is parallel to the chord joining the end points of the arc.
  • 1 answers

Satyam Jha 6 years, 10 months ago

Given: A circle with Centre O, P is the midpoint of  Arc APB. AB is chord of arc APB. PT is a tangent to the circle at P. To Prove:  AB || PT Construction: join OA ,OB, & OP Proof: OP ⟂PT [Radius is ⟂ to  tangent through point of contact] ∠OPT= 90° Since P is the midpoint of Arc APB Arc AAP =arc BP ∠AOP = ∠BOP ∠AOM= ∠BOM In ∆ AOM & ∆BOM OA= OB= r OM = OM           (Common) ∠AOM= ∠BOM   (proved above) ∠AOM≅∠BOM   (by SAS congruency  axiom) ∠AMO = ∠BMO      (c.p.c.t) ∠AMO + ∠BMO= 180° ∠AMO = ∠BMO= 90° ∠BMO = ∠OPT= 90° But,  they are corresponding angles. Hence, AB||PT HOPE THIS WILL HELP YOU... .
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